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Pythagorean Identity

Understanding the Pythagorean Identity

The Pythagorean Identity is one of the most fundamental relationships in trigonometry. It is directly derived from the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) applied to a right triangle within the unit circle, where the hypotenuse is 11, the opposite side is sinθ\sin \theta, and the adjacent side is cosθ\cos \theta.

The Three Forms of the Identity

The primary Pythagorean Identity is: sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

By dividing this fundamental equation by either cos2θ\cos^2 \theta or sin2θ\sin^2 \theta, we can derive two other useful forms:

  1. Divide by cos2θ\cos^2 \theta: tan2θ+1=sec2θ\tan^2 \theta + 1 = \sec^2 \theta

  2. Divide by sin2θ\sin^2 \theta: 1+cot2θ=csc2θ1 + \cot^2 \theta = \csc^2 \theta

These identities are essential tools for finding missing trigonometric values and simplifying complex expressions.

Finding Trigonometric Values

You can use the Pythagorean Identity to find an unknown trigonometric value if you know another one and the quadrant where the angle lies.

Example: If sinθ=35\sin \theta = \frac{3}{5} and θ\theta is in Quadrant II, find cosθ\cos \theta and tanθ\tan \theta.

Solution:

  1. Start with the main identity: sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1
  2. Substitute the known value: (35)2+cos2θ=1\left(\frac{3}{5}\right)^2 + \cos^2 \theta = 1 925+cos2θ=1\frac{9}{25} + \cos^2 \theta = 1
  3. Solve for cos2θ\cos^2 \theta: cos2θ=1925=1625\cos^2 \theta = 1 - \frac{9}{25} = \frac{16}{25}
  4. Take the square root. Since θ\theta is in Quadrant II, the cosine value must be negative: cosθ=45\cos \theta = -\frac{4}{5}
  5. Find tanθ\tan \theta using the quotient identity (tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta}): tanθ=3545=34\tan \theta = \frac{\frac{3}{5}}{-\frac{4}{5}} = -\frac{3}{4}

Simplifying Trigonometric Expressions

The identities are also used to rewrite and simplify expressions.

Example: Simplify 1cos2θsinθ\frac{1 - \cos^2 \theta}{\sin \theta}.

Solution:

  1. Recognize that from sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1, we can rearrange it to get: 1cos2θ=sin2θ1 - \cos^2 \theta = \sin^2 \theta
  2. Substitute this back into the numerator of the original expression: sin2θsinθ\frac{\sin^2 \theta}{\sin \theta}
  3. Cancel out a common factor of sinθ\sin \theta: sinθ\sin \theta

The simplified expression is simply sinθ\sin \theta.