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Sigma Notation & Series Properties

Sigma Notation and Series Properties

When working with long sequences of numbers, writing out every term of a series can be tedious. Sigma notation provides a compact way to represent the sum of a sequence.

What is Sigma Notation?

The Greek capital letter Sigma (Σ\Sigma) is used in mathematics to denote a sum. A typical series written in sigma notation looks like this: k=1nak\sum_{k=1}^{n} a_k

  • kk is the index of summation (often represented by ii, jj, or kk).
  • k=1k=1 is the lower limit, telling you the starting value of the index.
  • nn is the upper limit, telling you the final value of the index.
  • aka_k is the general formula for the terms being added.

Example: Write 3+6+9++603 + 6 + 9 + \cdots + 60 using sigma notation. Notice that each term is a multiple of 3: 3(1)+3(2)+3(3)++3(20)3(1) + 3(2) + 3(3) + \cdots + 3(20). We can write this compactly as: k=1203k\sum_{k=1}^{20} 3k

Properties of Series (Linearity)

Sigma notation follows specific algebraic rules that make it easier to manipulate and evaluate sums.

  1. Constant Multiple Rule: You can factor a constant out of a summation. k=1ncak=ck=1nak\sum_{k=1}^{n} c \cdot a_k = c \sum_{k=1}^{n} a_k

  2. Addition and Subtraction Rules: The sum of a sum (or difference) is the sum (or difference) of the sums. k=1n(ak±bk)=k=1nak±k=1nbk\sum_{k=1}^{n} (a_k \pm b_k) = \sum_{k=1}^{n} a_k \pm \sum_{k=1}^{n} b_k

Common Summation Formulas

Instead of adding terms one by one, you can use these standard formulas for common series starting at k=1k=1:

  • Sum of a constant: k=1nc=cn\sum_{k=1}^{n} c = cn
  • Sum of the first nn integers: k=1nk=n(n+1)2\sum_{k=1}^{n} k = \frac{n(n+1)}{2}
  • Sum of the first nn squares: k=1nk2=n(n+1)(2n+1)6\sum_{k=1}^{n} k^2 = \frac{n(n+1)(2n+1)}{6}

Example Problem

Evaluate k=150k\sum_{k=1}^{50} k

This notation asks for the sum of the first 50 positive integers: 1+2+3++501 + 2 + 3 + \cdots + 50. Instead of adding them manually, use the formula for the sum of the first nn integers, where n=50n = 50: k=150k=50(50+1)2\sum_{k=1}^{50} k = \frac{50(50 + 1)}{2} =50×512= \frac{50 \times 51}{2} =25×51=1275= 25 \times 51 = 1275

The sum of the series is 12751275.