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Absolute Value in Expressions and Equations

Absolute Value in Expressions and Equations

The absolute value of a number represents its distance from zero on the number line. Because distance cannot be negative, absolute value is always positive (or zero). We use the symbol โˆฃxโˆฃ|x| to denote the absolute value of xx.

Evaluating Absolute Value Expressions

When evaluating expressions that contain absolute value bars, treat the bars like parentheses. First, substitute the given value, then simplify the expression inside the absolute value bars, apply the absolute value, and finally perform the remaining operations.

Example: Evaluate โˆฃxโˆ’3โˆฃ+โˆฃx+2โˆฃ|x - 3| + |x + 2| when x=1x = 1.

  1. Substitute x=1x = 1 into the expression: โˆฃ1โˆ’3โˆฃ+โˆฃ1+2โˆฃ|1 - 3| + |1 + 2|
  2. Simplify inside the absolute value bars: โˆฃโˆ’2โˆฃ+โˆฃ3โˆฃ|-2| + |3|
  3. Find the absolute values (โˆฃโˆ’2โˆฃ=2|-2| = 2 and โˆฃ3โˆฃ=3|3| = 3): 2+32 + 3
  4. Add the results together: 2+3=52 + 3 = 5

Finding Distance on the Number Line

Absolute value is incredibly useful for finding the exact distance between any two points on a number line. The distance between two numbers, aa and bb, is given by the formula: Distance=โˆฃaโˆ’bโˆฃ\text{Distance} = |a - b| (Note: โˆฃbโˆ’aโˆฃ|b - a| gives the exact same result!)

Example: Find the distance between โˆ’7-7 and 44 on the number line.

  1. Set a=โˆ’7a = -7 and b=4b = 4.
  2. Plug them into the distance formula: โˆฃโˆ’7โˆ’4โˆฃ|-7 - 4|
  3. Simplify inside the bars: โˆฃโˆ’11โˆฃ|-11|
  4. Find the absolute value: โˆฃโˆ’11โˆฃ=11|-11| = 11

The distance between โˆ’7-7 and 44 is 1111 units.

Solving Distance Equations

Sometimes you know the distance and a starting point, but you need to find the ending point. Because you can move in two directions on a number line (left or right), there are usually two answers!

Example: Find all values of xx on the number line that are a distance of 55 from โˆ’2-2.

This means we are starting at โˆ’2-2 and moving 55 units in both directions.

  • Moving right (adding): โˆ’2+5=3-2 + 5 = 3
  • Moving left (subtracting): โˆ’2โˆ’5=โˆ’7-2 - 5 = -7

So, the values of xx are 33 and โˆ’7-7. We can write this as an absolute value equation: โˆฃxโˆ’(โˆ’2)โˆฃ=5|x - (-2)| = 5, which simplifies to โˆฃx+2โˆฃ=5|x + 2| = 5. Both x=3x = 3 and x=โˆ’7x = -7 make this equation true!