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Volume with Fractional Edges

Volume with Fractional Edge Lengths

Finding the volume of a rectangular prism when the sides are fractions or mixed numbers works exactly the same way as when the sides are whole numbers. You can solve these problems using the standard volume formula or by visualizing how many fractional unit cubes fit inside.

Using the Volume Formula

The formula for the volume of a rectangular prism is:

V=lร—wร—hV = l \times w \times h

Where ll is length, ww is width, and hh is height.

Example: Find the volume of a rectangular prism with dimensions 212ร—3ร—1142\frac{1}{2} \times 3 \times 1\frac{1}{4}.

Step 1: Convert all numbers, including mixed numbers, to improper fractions.

  • 212=522\frac{1}{2} = \frac{5}{2}
  • 3=313 = \frac{3}{1}
  • 114=541\frac{1}{4} = \frac{5}{4}

Step 2: Multiply the fractions. Multiply the numerators together, and the denominators together:

V=52ร—31ร—54=5ร—3ร—52ร—1ร—4=758V = \frac{5}{2} \times \frac{3}{1} \times \frac{5}{4} = \frac{5 \times 3 \times 5}{2 \times 1 \times 4} = \frac{75}{8}

Step 3: Convert back to a mixed number (if needed).

758=938\frac{75}{8} = 9\frac{3}{8}

The volume is 9389\frac{3}{8} cubic units.

Packing with Fractional Unit Cubes

Sometimes, you are asked to find volume by figuring out how many smaller, fractional cubes can pack into a larger box.

Example: How many 12\frac{1}{2}-inch cubes fit inside a rectangular box measuring 33 inches by 22 inches by 11 inch?

Step 1: Find out how many cubes fit along each side. To do this, divide each side length of the box by the side length of the small cube (12\frac{1}{2} inch).

  • Length: 3รท12=3ร—2=63 \div \frac{1}{2} = 3 \times 2 = 6 cubes
  • Width: 2รท12=2ร—2=42 \div \frac{1}{2} = 2 \times 2 = 4 cubes
  • Height: 1รท12=1ร—2=21 \div \frac{1}{2} = 1 \times 2 = 2 cubes

Step 2: Multiply the number of cubes. Now, multiply the number of cubes that fit along the length, width, and height:

6ร—4ร—2=486 \times 4 \times 2 = 48

Exactly 4848 of the 12\frac{1}{2}-inch cubes will fit perfectly inside the box.