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Multi-Digit by 1-Digit Division

Dividing Multi-Digit by One-Digit Numbers

Dividing large numbers by a single digit is like sharing a big pile of items into a few equal groups. In 4th grade, you will learn to divide numbers up to four digits long by a one-digit number. You can solve these problems using Standard Long Division or Partial Quotients.

Standard Long Division

Long division breaks the problem down into smaller, step-by-step division problems from left to right. A helpful way to remember the steps is: Divide, Multiply, Subtract, Bring down.

Let's solve 852÷4852 \div 4:

  1. Divide the hundreds: How many times does 44 go into 88? Exactly 22 times. Write 22 above the 88.
  2. Multiply & Subtract: 2×4=82 \times 4 = 8. Subtract 88=08 - 8 = 0.
  3. Bring down: Bring down the next digit, which is 55.
  4. Divide the tens: How many times does 44 go into 55? It goes in 11 time. Write 11 above the 55.
  5. Multiply & Subtract: 1×4=41 \times 4 = 4. Subtract 54=15 - 4 = 1.
  6. Bring down: Bring down the last digit, 22, making the new number 1212.
  7. Divide the ones: How many times does 44 go into 1212? Exactly 33 times. Write 33 above the 22.

Since 3×4=123 \times 4 = 12 and 1212=012 - 12 = 0, there is no remainder. The answer is 213213.

Division with Remainders

Sometimes, a number cannot be divided perfectly into equal groups. The amount left over is called the remainder.

Let's solve 3,645÷73{,}645 \div 7:

  1. Thousands: 3÷73 \div 7 doesn't work (since 33 is smaller than 77). So, we look at the first two digits: 3636.
  2. Hundreds: 36÷7=536 \div 7 = 5 (since 5×7=355 \times 7 = 35). Subtract 3635=136 - 35 = 1. Bring down the 44 to make 1414.
  3. Tens: 14÷7=214 \div 7 = 2. Write 22 on top. Subtract 1414=014 - 14 = 0. Bring down the 55.
  4. Ones: 5÷7=05 \div 7 = 0. Write 00 on top. Subtract 50=55 - 0 = 5.

There are no more numbers to bring down, and 55 is smaller than 77. Our final answer is 520520 with a remainder of 55, often written as 520 R 5520 \text{ R } 5.

Using Partial Quotients

Partial quotients is a method where you take out easy "chunks" of the divisor until nothing is left.

Let's look at 852÷4852 \div 4 again:

  • Take out a big chunk: I know 4×200=8004 \times 200 = 800. Let's subtract 800800 from 852852. 852800=52852 - 800 = 52 (Partial quotient so far: 200)
  • Take out another chunk: I know 4×10=404 \times 10 = 40. Let's subtract 4040 from 5252. 5240=1252 - 40 = 12 (Partial quotient so far: 10)
  • Take out the last chunk: I know 4×3=124 \times 3 = 12. Subtract 1212 from 1212. 1212=012 - 12 = 0 (Partial quotient so far: 3)

Finally, add up all your partial quotients: 200+10+3=213200 + 10 + 3 = 213. Both methods give you the same correct answer!