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Linear Equations in One Variable

Linear Equations in One Variable

A linear equation in one variable is an equation that can be written in the form ax+b=0ax + b = 0, where aa and bb are constants and xx is the variable. In Grade 9, these equations become more complex, often featuring variables on both sides, parentheses, or unknown coefficients.

The Standard Solving Process

To solve a linear equation, your main goal is to isolate the variable on one side of the equals sign. Follow these steps:

  1. Distribute to remove any parentheses.
  2. Combine like terms on each side of the equation.
  3. Move variables to one side (using addition or subtraction).
  4. Isolate the variable by multiplying or dividing.

Example: Solve 3(x2)=2x+53(x - 2) = 2x + 5

First, distribute the 33: 3x6=2x+53x - 6 = 2x + 5

Next, subtract 2x2x from both sides to get all xx's on the left: x6=5x - 6 = 5

Finally, add 66 to both sides: x=11x = 11

Equations with Unknown Coefficients

Sometimes, an equation includes other letters (parameters) instead of numbers. You treat these exactly like numbers and factor out the variable to isolate it.

Example: Solve ax+3=bx1ax + 3 = bx - 1 for xx

Move all terms containing xx to one side, and constants to the other. Subtract bxbx and subtract 33: axbx=13ax - bx = -1 - 3 axbx=4ax - bx = -4

Now, factor out the xx on the left side: x(ab)=4x(a - b) = -4

Divide both sides by (ab)(a - b) to isolate xx (assuming aba \neq b): x=4abx = \frac{-4}{a - b}

Number of Solutions

Not all linear equations have exactly one solution. By simplifying an equation, you can determine how many solutions it has:

  • One Solution: The equation simplifies to x=numberx = \text{number}. The lines intersect at one point.
  • No Solution: The equation simplifies to a false statement, like 3=53 = 5. This means no value of xx will ever make the equation true.
  • Infinitely Many Solutions: The equation simplifies to a true statement, like 4=44 = 4 or x=xx = x. This means any real number is a valid solution.

Example: Determine the number of solutions for 4(x+1)=4x+44(x + 1) = 4x + 4

Distribute the 44 on the left side: 4x+4=4x+44x + 4 = 4x + 4

Subtract 4x4x from both sides: 4=44 = 4

Because 4=44 = 4 is always a true statement, regardless of what xx is, this equation has infinitely many solutions.