Facebook Pixel
Mathos AI logo

Absolute Value Inequalities

Absolute Value Inequalities

An absolute value expression measures the distance of a number from zero on a number line. When we solve absolute value inequalities, we are finding a range of values whose distance from zero meets a certain condition.

To solve these, we remove the absolute value bars by translating the problem into a compound inequality. There are two main types depending on the inequality sign.

1. "Less Than" Inequalities (<< or \le)

When the absolute value is less than a positive number cc, the distance from zero is strictly within the range between c-c and cc. This creates an "and" compound inequality.

Rule: If A<c|A| < c, then: c<A<c-c < A < c

(Note: The same rule applies to \le, just use \le in your compound inequality.)

Example: Solve x4<3|x - 4| < 3

  1. Set up the compound inequality: 3<x4<3-3 < x - 4 < 3
  2. Add 4 to all three parts to isolate xx: 3+4<x4+4<3+4-3 + 4 < x - 4 + 4 < 3 + 4 1<x<71 < x < 7 The solution is all numbers strictly between 1 and 7.

2. "Greater Than" Inequalities (>> or \ge)

When the absolute value is greater than a positive number cc, the distance from zero is further away than cc. This means the expression inside must be either very positive or very negative. This creates an "or" compound inequality.

Rule: If A>c|A| > c, then: A>corA<cA > c \quad \text{or} \quad A < -c

Example: Solve 2x+15|2x + 1| \ge 5

  1. Split into two separate inequalities: 2x+15or2x+152x + 1 \ge 5 \quad \text{or} \quad 2x + 1 \le -5
  2. Solve the first inequality: 2x4    x22x \ge 4 \implies x \ge 2
  3. Solve the second inequality: 2x6    x32x \le -6 \implies x \le -3 The solution is x3 or x2x \le -3 \text{ or } x \ge 2.

A Quick Tip for Memorization

  • Less thAND: << or \le translates to an AND inequality (a single, connected range).
  • GreatOR: >> or \ge translates to an OR inequality (two separate ranges pointing outward).