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Polygon Angle Sums

Polygon Angle Sums

When working with polygons, understanding how their angles relate to the number of sides is a fundamental geometry skill. Whether you are dealing with a simple triangle or a complex 12-sided figure, specific formulas allow you to find the sums of their interior and exterior angles.

Sum of Interior Angles

The interior angles are the angles inside the closed shape of a polygon. The sum of the interior angles of any nn-sided polygon is given by the formula:

Sum=(n2)×180\text{Sum} = (n - 2) \times 180^\circ

Why does this work? If you pick one vertex of a polygon and draw diagonals to all other non-adjacent vertices, you will divide the polygon into exactly n2n - 2 triangles. Since the interior angles of a single triangle always add up to 180180^\circ, multiplying the number of triangles by 180180^\circ gives the total angle sum.

Example: Find the sum of the interior angles of a 12-gon.

  • Identify the number of sides: n=12n = 12
  • Apply the formula: S=(122)×180S = (12 - 2) \times 180^\circ
  • Calculate: S=10×180=1800S = 10 \times 180^\circ = 1800^\circ

Sum of Exterior Angles

An exterior angle is formed by extending one side of the polygon outward. The rule for exterior angles is beautifully simple:

The sum of the exterior angles of any convex polygon (taking one at each vertex) is always 360360^\circ, regardless of how many sides the polygon has.

Regular Polygons

A regular polygon has all sides equal in length and all interior angles equal in measure. Because the angles are identical, you can easily find the measure of a single angle by dividing the total sum by the number of sides, nn.

Each Interior Angle: Interior Angle=(n2)×180n\text{Interior Angle} = \frac{(n - 2) \times 180^\circ}{n}

Each Exterior Angle: Exterior Angle=360n\text{Exterior Angle} = \frac{360^\circ}{n}

(Note: The interior and exterior angle at the same vertex always add up to 180180^\circ.)

Example: Find each interior angle of a regular octagon.

  • An octagon has n=8n = 8 sides.
  • Total interior sum: (82)×180=6×180=1080(8 - 2) \times 180^\circ = 6 \times 180^\circ = 1080^\circ
  • Divide by 8: 10808=135\frac{1080^\circ}{8} = 135^\circ

Alternatively, you can find the exterior angle first (3608=45\frac{360^\circ}{8} = 45^\circ) and subtract it from 180180^\circ (18045=135180^\circ - 45^\circ = 135^\circ). Both methods work perfectly!